4(x^2+3x+36)=20

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Solution for 4(x^2+3x+36)=20 equation: 



4(x^2+3x+36)=20

We move all terms to the left:

4(x^2+3x+36)-(20)=0

We multiply parentheses

4x^2+12x+144-20=0

We add all the numbers together, and all the variables

4x^2+12x+124=0

a = 4; b = 12; c = +124;
Δ = b2-4ac
Δ = 122-4·4·124
Δ = -1840
Delta is less than zero, so there is no solution for the equation

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